Sebanyak 6 gram urea (M₁ = 60) dilarutkan dalam 500 gram air. Tentukan titik didih larutan (Kbair=0,52°C/m)?
Penjelasan:
massa = 6 gram
Mr = 60
p = 500 gram
Kb = 0,52°C/m
Titik didih larutan (Tb laruta ) ... ?
ΔTb = Kb . m
ΔTb = Kb . (massa/Mr . 1000/p)
ΔTb = 0,52 . (6/60 . 1000/500)
ΔTb = 0,52 . 0,2
ΔTb = 0,104°C
ΔTb = Tb larutan - Tb pelarut
0,104°C = Tb larutan - 100°C
Tb larutan = 100°C + 0,104°C
Tb larutan = 1,104°C
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